14x^2+12x-6=-6

Solution for 14x^2+12x-6=-6 equation:

14x^2+12x-6=-6

We move all terms to the left:

14x^2+12x-6-(-6)=0

We add all the numbers together, and all the variables

14x^2+12x=0

a = 14; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·14·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*14}=\frac{-24}{28}
=-6/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*14}=\frac{0}{28}
=0
$